(x+3)(x^4-4x^2+5)=

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Solution for (x+3)(x^4-4x^2+5)= equation: 


Simplifying
(x + 3)(x4 + -4x2 + 5) = 0

Reorder the terms:
(3 + x)(x4 + -4x2 + 5) = 0

Reorder the terms:
(3 + x)(5 + -4x2 + x4) = 0

Multiply (3 + x) * (5 + -4x2 + x4)
(3(5 + -4x2 + x4) + x(5 + -4x2 + x4)) = 0
((5 * 3 + -4x2 * 3 + x4 * 3) + x(5 + -4x2 + x4)) = 0
((15 + -12x2 + 3x4) + x(5 + -4x2 + x4)) = 0
(15 + -12x2 + 3x4 + (5 * x + -4x2 * x + x4 * x)) = 0
(15 + -12x2 + 3x4 + (5x + -4x3 + x5)) = 0

Reorder the terms:
(15 + 5x + -12x2 + -4x3 + 3x4 + x5) = 0
(15 + 5x + -12x2 + -4x3 + 3x4 + x5) = 0

Solving
15 + 5x + -12x2 + -4x3 + 3x4 + x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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